What are the solutions to the equation (3r+2)^2=5 ?

The solutions to the equation (3r+2)^2=5 are r=(sqrt(5)-2)/3 ,r=(-sqrt(5)-2)/3

Find the zeros of (3r+2)^2=5

The zeros of (3r+2)^2=5 are r=(sqrt(5)-2)/3 ,r=(-sqrt(5)-2)/3

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(3 r + 2)^{2} = 5

r = \frac{5 - 2}{3}, r = \frac{- 5 - 2}{3}

Decimal Notation

r = 0.07868 \dots, r = - 1.41202 \dots

Solution steps

(3 r + 2)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 r + 2 = 5 : r = \frac{5 - 2}{3}

Solve

3 r + 2 = - 5 : r = \frac{- 5 - 2}{3}

The solutions to the quadratic equation are:

r = \frac{5 - 2}{3}, r = \frac{- 5 - 2}{3}

2 x^{2} - 14 x + 10 = 26

0 = - 4.9 t^{2} + 9.8 t + 14.7

(y + 3)^{2} - 49 = 0

x^{2} + 4 = 5

x^{2} - 4 x - 63 = - 6 x

What are the solutions to the equation (3r+2)^2=5 ?
The solutions to the equation (3r+2)^2=5 are r=(sqrt(5)-2)/3 ,r=(-sqrt(5)-2)/3
Find the zeros of (3r+2)^2=5
The zeros of (3r+2)^2=5 are r=(sqrt(5)-2)/3 ,r=(-sqrt(5)-2)/3