What are the solutions to the equation A(x)=x((288-2x)/2) ?

The solutions to the equation A(x)=x((288-2x)/2) are x=0,x=-A+144

Find the zeros of A(x)=x((288-2x)/2)

The zeros of A(x)=x((288-2x)/2) are x=0,x=-A+144

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A (x) = x (\frac{288 - 2 x}{2})

x = 0, x = - A + 144

Solution steps

A (x) = x (\frac{288 - 2 x}{2})

Move

x (\frac{288 - 2 x}{2})

to the left side

A x - x \frac{288 - 2 x}{2} = 0

Factor

A x - x \frac{288 - 2 x}{2} : x (A - 144 + x)

x (A - 144 + x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or A - 144 + x = 0

Solve

A - 144 + x = 0 : x = - A + 144

The solutions to the quadratic equation are:

x = 0, x = - A + 144

(2 x + 1) (4 x^{2} - 2 x + 1) - 1 = 1.6 x^{2} (5 x - 2)

9 x^{2} - 12 x + 5

x^{2} + 6 x + 1 = - 2 x + 1

2 p^{2} - 7 p = 5

3 (x - 4)^{2} = 27

What are the solutions to the equation A(x)=x((288-2x)/2) ?
The solutions to the equation A(x)=x((288-2x)/2) are x=0,x=-A+144
Find the zeros of A(x)=x((288-2x)/2)
The zeros of A(x)=x((288-2x)/2) are x=0,x=-A+144