What are the solutions to the equation 3x^2-2x=x-1 ?

The solutions to the equation 3x^2-2x=x-1 are x= 1/2+i(sqrt(3))/6 ,x= 1/2-i(sqrt(3))/6

Find the zeros of 3x^2-2x=x-1

The zeros of 3x^2-2x=x-1 are x= 1/2+i(sqrt(3))/6 ,x= 1/2-i(sqrt(3))/6

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3 x^{2} - 2 x = x - 1

x = \frac{1}{2} + i \frac{3}{6}, x = \frac{1}{2} - i \frac{3}{6}

Solution steps

3 x^{2} - 2 x = x - 1

Move

1

to the left side

3 x^{2} - 2 x + 1 = x

Move

x

to the left side

3 x^{2} - 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

Simplify

(- 3)^{2} - 4 \cdot 3 \cdot 1 : 3 i

x_{1, 2} = \frac{- ( - 3 ) \pm 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 i}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 3 i}{2 \cdot 3}

x = \frac{- ( - 3 ) + 3 i}{2 \cdot 3} : \frac{1}{2} + i \frac{3}{6}

x = \frac{- ( - 3 ) - 3 i}{2 \cdot 3} : \frac{1}{2} - i \frac{3}{6}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{3}{6}, x = \frac{1}{2} - i \frac{3}{6}

x^{2} - 2 = 2 x - 2

x, 14 x^{2} + 36 x y - y^{2} - 3 x - 2 y = 0

x^{2} - 41 = - 5

- 45 = 10 t - 4.9 t^{2}

x, y = 4 - (x + 2)^{2}

What are the solutions to the equation 3x^2-2x=x-1 ?
The solutions to the equation 3x^2-2x=x-1 are x= 1/2+i(sqrt(3))/6 ,x= 1/2-i(sqrt(3))/6
Find the zeros of 3x^2-2x=x-1
The zeros of 3x^2-2x=x-1 are x= 1/2+i(sqrt(3))/6 ,x= 1/2-i(sqrt(3))/6