What are the solutions to the equation x^2-2=2x-2 ?

The solutions to the equation x^2-2=2x-2 are x=2,x=0

Find the zeros of x^2-2=2x-2

The zeros of x^2-2=2x-2 are x=2,x=0

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x^{2} - 2 = 2 x - 2

x = 2, x = 0

Solution steps

x^{2} - 2 = 2 x - 2

Move

2

to the left side

x^{2} = 2 x

Move

2 x

to the left side

x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

x = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

x, 14 x^{2} + 36 x y - y^{2} - 3 x - 2 y = 0

x^{2} - 41 = - 5

- 45 = 10 t - 4.9 t^{2}

x, y = 4 - (x + 2)^{2}

x^{2} - 9 x - 20 = - 2 x - 2

What are the solutions to the equation x^2-2=2x-2 ?
The solutions to the equation x^2-2=2x-2 are x=2,x=0
Find the zeros of x^2-2=2x-2
The zeros of x^2-2=2x-2 are x=2,x=0