What are the solutions to the equation v^2+3v-2=0 ?

The solutions to the equation v^2+3v-2=0 are v=(-3+sqrt(17))/2 ,v=(-3-sqrt(17))/2

Find the zeros of v^2+3v-2=0

The zeros of v^2+3v-2=0 are v=(-3+sqrt(17))/2 ,v=(-3-sqrt(17))/2

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v^{2} + 3 v - 2 = 0

v = \frac{- 3 + 17}{2}, v = \frac{- 3 - 17}{2}

Decimal Notation

v = 0.56155 \dots, v = - 3.56155 \dots

Solution steps

v^{2} + 3 v - 2 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 2) = 17

v_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 3 + 17}{2 \cdot 1}, v_{2} = \frac{- 3 - 17}{2 \cdot 1}

v = \frac{- 3 + 17}{2 \cdot 1} : \frac{- 3 + 17}{2}

v = \frac{- 3 - 17}{2 \cdot 1} : \frac{- 3 - 17}{2}

The solutions to the quadratic equation are:

v = \frac{- 3 + 17}{2}, v = \frac{- 3 - 17}{2}

x^{2} - 13 x + 24 = - x + 4

4 x (3 x - 5) = 0

6 x^{2} - 19 x = - 10

x^{2} - 9 x + 1 = 1

6 x^{2} - 17 x - 54 = 2 x^{2} - 11 x

What are the solutions to the equation v^2+3v-2=0 ?
The solutions to the equation v^2+3v-2=0 are v=(-3+sqrt(17))/2 ,v=(-3-sqrt(17))/2
Find the zeros of v^2+3v-2=0
The zeros of v^2+3v-2=0 are v=(-3+sqrt(17))/2 ,v=(-3-sqrt(17))/2