What are the solutions to the equation 4r^2-5r-6=0 ?

The solutions to the equation 4r^2-5r-6=0 are r=2,r=-3/4

Find the zeros of 4r^2-5r-6=0

The zeros of 4r^2-5r-6=0 are r=2,r=-3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 r^{2} - 5 r - 6 = 0

r = 2, r = - \frac{3}{4}

Decimal

r = 2, r = - 0.75

Solution steps

4 r^{2} - 5 r - 6 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 6) = 11

r_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 4}

Separate the solutions

r_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 4}, r_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 4}

r = \frac{- ( - 5 ) + 11}{2 \cdot 4} : 2

r = \frac{- ( - 5 ) - 11}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

r = 2, r = - \frac{3}{4}

4 x^{2} - 27 x + 18 = 0

2 c^{2} - 9 c - 2 = 0

2 m^{2} - 16 m + 8 = 0

x^{2} - 10 x + 18 = x

x^{2} - x + 5 = 5

What are the solutions to the equation 4r^2-5r-6=0 ?
The solutions to the equation 4r^2-5r-6=0 are r=2,r=-3/4
Find the zeros of 4r^2-5r-6=0
The zeros of 4r^2-5r-6=0 are r=2,r=-3/4