What are the solutions to the equation 10x^2-20x+1=0 ?

The solutions to the equation 10x^2-20x+1=0 are x=(10+3sqrt(10))/(10),x=(10-3sqrt(10))/(10)

Find the zeros of 10x^2-20x+1=0

The zeros of 10x^2-20x+1=0 are x=(10+3sqrt(10))/(10),x=(10-3sqrt(10))/(10)

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10 x^{2} - 20 x + 1 = 0

x = \frac{10 + 3 10}{10}, x = \frac{10 - 3 10}{10}

Decimal

x = 1.94868 \dots, x = 0.05131 \dots

Solution steps

10 x^{2} - 20 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 10 \cdot 1}{2 \cdot 10}

(- 20)^{2} - 4 \cdot 10 \cdot 1 = 610

x_{1, 2} = \frac{- ( - 20 ) \pm 6 10}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 6 10}{2 \cdot 10}, x_{2} = \frac{- ( - 20 ) - 6 10}{2 \cdot 10}

x = \frac{- ( - 20 ) + 6 10}{2 \cdot 10} : \frac{10 + 3 10}{10}

x = \frac{- ( - 20 ) - 6 10}{2 \cdot 10} : \frac{10 - 3 10}{10}

The solutions to the quadratic equation are:

x = \frac{10 + 3 10}{10}, x = \frac{10 - 3 10}{10}

x^{2} - 25 x + 36 = 0

5 x^{2} - 7 x = - 4 x + 3 x^{2}

x^{2} + 9 = 4 x

- 6 m^{2} - 6 = - 7 m - 9

k^{2} = 3 k

What are the solutions to the equation 10x^2-20x+1=0 ?
The solutions to the equation 10x^2-20x+1=0 are x=(10+3sqrt(10))/(10),x=(10-3sqrt(10))/(10)
Find the zeros of 10x^2-20x+1=0
The zeros of 10x^2-20x+1=0 are x=(10+3sqrt(10))/(10),x=(10-3sqrt(10))/(10)