What are the solutions to the equation 9p^2-27p+20=0 ?

The solutions to the equation 9p^2-27p+20=0 are p= 5/3 ,p= 4/3

Find the zeros of 9p^2-27p+20=0

The zeros of 9p^2-27p+20=0 are p= 5/3 ,p= 4/3

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9 p^{2} - 27 p + 20 = 0

p = \frac{5}{3}, p = \frac{4}{3}

Decimal Notation

p = 1.66666 \dots, p = 1.33333 \dots

Solution steps

9 p^{2} - 27 p + 20 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 9 \cdot 20}{2 \cdot 9}

(- 27)^{2} - 4 \cdot 9 \cdot 20 = 3

p_{1, 2} = \frac{- ( - 27 ) \pm 3}{2 \cdot 9}

Separate the solutions

p_{1} = \frac{- ( - 27 ) + 3}{2 \cdot 9}, p_{2} = \frac{- ( - 27 ) - 3}{2 \cdot 9}

p = \frac{- ( - 27 ) + 3}{2 \cdot 9} : \frac{5}{3}

p = \frac{- ( - 27 ) - 3}{2 \cdot 9} : \frac{4}{3}

The solutions to the quadratic equation are:

p = \frac{5}{3}, p = \frac{4}{3}

x, x^{2} y^{2} - x - 4 y^{2} = 0

x^{2} - 2 x - 5 = - 5

x^{2} + 6 x - 49 = 6 x

x, 3 x^{2} + 2 x y - 3 y^{2} - 8 y - 2 = 0

x^{2} + (\frac{1}{6})^{2} = 1

What are the solutions to the equation 9p^2-27p+20=0 ?
The solutions to the equation 9p^2-27p+20=0 are p= 5/3 ,p= 4/3
Find the zeros of 9p^2-27p+20=0
The zeros of 9p^2-27p+20=0 are p= 5/3 ,p= 4/3