What is factor 2u(2u-3)^2+u^2(3-2u) ?

The solution to factor 2u(2u-3)^2+u^2(3-2u) is 3u(2u-3)(u-2)

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factor 2u(2u-3)^2+u^2(3-2u)

factor

2 u (2 u - 3)^{2} + u^{2} (3 - 2 u)

3 u (2 u - 3) (u - 2)

Solution steps

2 u (2 u - 3)^{2} + u^{2} (3 - 2 u)

u^{2} (3 - 2 u) = - u^{2} (2 u - 3)

= 2 u (2 u - 3)^{2} - u^{2} (2 u - 3)

Factor out common term

u (2 u - 3) : u (2 u - 3) (2 (2 u - 3) - u)

= u (2 u - 3) (2 (2 u - 3) - u)

Expand

2 (2 u - 3) - u : 3 u - 6

= u (2 u - 3) (3 u - 6)

Factor

3 u - 6 : 3 (u - 2)

= u (2 u - 3) \cdot 3 (u - 2)

= 3 u (2 u - 3) (u - 2)

16 x^{2} - 1

- 8 - 5 (4 k + 5) > - 7 k + 4 - 8 k

v^{2} - 36

- \frac{2}{5} \cdot 2

- 2 < x and 2 x + 6 < 14

What is factor 2u(2u-3)^2+u^2(3-2u) ?
The solution to factor 2u(2u-3)^2+u^2(3-2u) is 3u(2u-3)(u-2)