What are the solutions to the equation x^2+5x-18=-4 ?

The solutions to the equation x^2+5x-18=-4 are x=2,x=-7

Find the zeros of x^2+5x-18=-4

The zeros of x^2+5x-18=-4 are x=2,x=-7

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x^{2} + 5 x - 18 = - 4

x = 2, x = - 7

Solution steps

x^{2} + 5 x - 18 = - 4

Move

4

to the left side

x^{2} + 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 9}{2 \cdot 1}, x_{2} = \frac{- 5 - 9}{2 \cdot 1}

x = \frac{- 5 + 9}{2 \cdot 1} : 2

x = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 2, x = - 7

5 x^{2} - 12 x + 6 = 2

8 p^{2} - 26 p + 15 = 0

x, 6 x^{2} + 18 y^{2} + 36 y - 4 x + 56 = 0

4 x^{2} + x + 14 = 0

x^{2} + x - 12 = x + 4

What are the solutions to the equation x^2+5x-18=-4 ?
The solutions to the equation x^2+5x-18=-4 are x=2,x=-7
Find the zeros of x^2+5x-18=-4
The zeros of x^2+5x-18=-4 are x=2,x=-7