What are the solutions to the equation x^2-8x+48=0 ?

The solutions to the equation x^2-8x+48=0 are x=4+4sqrt(2)i,x=4-4sqrt(2)i

Find the zeros of x^2-8x+48=0

The zeros of x^2-8x+48=0 are x=4+4sqrt(2)i,x=4-4sqrt(2)i

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x^{2} - 8 x + 48 = 0

x = 4 + 42 i, x = 4 - 42 i

Solution steps

x^{2} - 8 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 48}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 48 : 82 i

x_{1, 2} = \frac{- ( - 8 ) \pm 8 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8 2 i}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8 2 i}{2 \cdot 1} : 4 + 42 i

x = \frac{- ( - 8 ) - 8 2 i}{2 \cdot 1} : 4 - 42 i

The solutions to the quadratic equation are:

x = 4 + 42 i, x = 4 - 42 i

x^{2} - 14 = - 5

(x + 13)^{2} = (x + 12)^{2} + (x - 5)^{2}

4 (a^{2} - 3) = 6 a + 4 (a + 3)

x, 9 x^{2} + 4 y^{2} - 36 x - 8 y + 76 = 0

(x - 3)^{2} = - 2 x^{2}

What are the solutions to the equation x^2-8x+48=0 ?
The solutions to the equation x^2-8x+48=0 are x=4+4sqrt(2)i,x=4-4sqrt(2)i
Find the zeros of x^2-8x+48=0
The zeros of x^2-8x+48=0 are x=4+4sqrt(2)i,x=4-4sqrt(2)i