What are the solutions to the equation 2x^2-15x+2=0 ?

The solutions to the equation 2x^2-15x+2=0 are x=(15+sqrt(209))/4 ,x=(15-sqrt(209))/4

Find the zeros of 2x^2-15x+2=0

The zeros of 2x^2-15x+2=0 are x=(15+sqrt(209))/4 ,x=(15-sqrt(209))/4

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2 x^{2} - 15 x + 2 = 0

x = \frac{15 + 209}{4}, x = \frac{15 - 209}{4}

Decimal Notation

x = 7.36420 \dots, x = 0.13579 \dots

Solution steps

2 x^{2} - 15 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

(- 15)^{2} - 4 \cdot 2 \cdot 2 = 209

x_{1, 2} = \frac{- ( - 15 ) \pm 209}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 209}{2 \cdot 2}, x_{2} = \frac{- ( - 15 ) - 209}{2 \cdot 2}

x = \frac{- ( - 15 ) + 209}{2 \cdot 2} : \frac{15 + 209}{4}

x = \frac{- ( - 15 ) - 209}{2 \cdot 2} : \frac{15 - 209}{4}

The solutions to the quadratic equation are:

x = \frac{15 + 209}{4}, x = \frac{15 - 209}{4}

8 (5 - 3 b)^{2} + 14 (5 - 3 b) = 15

x^{2} + x - 22 = x + 3

12 - (x - 1)^{2} = x^{2} + 1

10 d^{2} + 15 d - 25 = 6 d^{2}

x, (x - a)^{2} + (y - b)^{2} = r^{2}

What are the solutions to the equation 2x^2-15x+2=0 ?
The solutions to the equation 2x^2-15x+2=0 are x=(15+sqrt(209))/4 ,x=(15-sqrt(209))/4
Find the zeros of 2x^2-15x+2=0
The zeros of 2x^2-15x+2=0 are x=(15+sqrt(209))/4 ,x=(15-sqrt(209))/4