What are the solutions to the equation solvefor x,3x^2-6x-3y^2+3=0 ?

The solutions to the equation solvefor x,3x^2-6x-3y^2+3=0 are x=1+y,x=1-y

Find the zeros of solvefor x,3x^2-6x-3y^2+3=0

The zeros of solvefor x,3x^2-6x-3y^2+3=0 are x=1+y,x=1-y

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solve for

x, 3 x^{2} - 6 x - 3 y^{2} + 3 = 0

x = 1 + y, x = 1 - y

Solution steps

3 x^{2} - 6 x - 3 y^{2} + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 3 y ^{2} + 3 )}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 (- 3 y^{2} + 3) : 6 y

x_{1, 2} = \frac{- ( - 6 ) \pm 6 y}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 y}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6 y}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6 y}{2 \cdot 3} : 1 + y

x = \frac{- ( - 6 ) - 6 y}{2 \cdot 3} : 1 - y

The solutions to the quadratic equation are:

x = 1 + y, x = 1 - y

x^{2} + 4 x - 65 = 4 x - 1

x^{2} - 4 x - 16 = - 4 x

5 m (2 m + 12) = 0

2 e^{2} = 10 e + 5

x^{2} - 1 = 3 (x + 1)^{2}

What are the solutions to the equation solvefor x,3x^2-6x-3y^2+3=0 ?
The solutions to the equation solvefor x,3x^2-6x-3y^2+3=0 are x=1+y,x=1-y
Find the zeros of solvefor x,3x^2-6x-3y^2+3=0
The zeros of solvefor x,3x^2-6x-3y^2+3=0 are x=1+y,x=1-y