What are the solutions to the equation 8b^2+14b-9=6 ?

The solutions to the equation 8b^2+14b-9=6 are b= 3/4 ,b=-5/2

Find the zeros of 8b^2+14b-9=6

The zeros of 8b^2+14b-9=6 are b= 3/4 ,b=-5/2

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8 b^{2} + 14 b - 9 = 6

b = \frac{3}{4}, b = - \frac{5}{2}

Decimal Notation

b = 0.75, b = - 2.5

Solution steps

8 b^{2} + 14 b - 9 = 6

Move

6

to the left side

8 b^{2} + 14 b - 15 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 8 ( - 15 )}{2 \cdot 8}

1 4^{2} - 4 \cdot 8 (- 15) = 26

b_{1, 2} = \frac{- 14 \pm 26}{2 \cdot 8}

Separate the solutions

b_{1} = \frac{- 14 + 26}{2 \cdot 8}, b_{2} = \frac{- 14 - 26}{2 \cdot 8}

b = \frac{- 14 + 26}{2 \cdot 8} : \frac{3}{4}

b = \frac{- 14 - 26}{2 \cdot 8} : - \frac{5}{2}

The solutions to the quadratic equation are:

b = \frac{3}{4}, b = - \frac{5}{2}

x^{2} - 0.3 x - 0.1 = 0

2 x^{2} - 6 x - 6 = 0

5 x (x + 8) = 0

x^{2} + 18 = 82

x^{2} - 7 x - 54 = - 4 x

What are the solutions to the equation 8b^2+14b-9=6 ?
The solutions to the equation 8b^2+14b-9=6 are b= 3/4 ,b=-5/2
Find the zeros of 8b^2+14b-9=6
The zeros of 8b^2+14b-9=6 are b= 3/4 ,b=-5/2