What are the solutions to the equation 4/3 (x+1)^2+16=0 ?

The solutions to the equation 4/3 (x+1)^2+16=0 are x=2sqrt(3)i-1,x=-2sqrt(3)i-1

Find the zeros of 4/3 (x+1)^2+16=0

The zeros of 4/3 (x+1)^2+16=0 are x=2sqrt(3)i-1,x=-2sqrt(3)i-1

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\frac{4}{3} (x + 1)^{2} + 16 = 0

x = 23 i - 1, x = - 23 i - 1

Solution steps

\frac{4}{3} (x + 1)^{2} + 16 = 0

Move

16

to the right side

\frac{4}{3} (x + 1)^{2} = - 16

Multiply both sides by

3

4 (x + 1)^{2} = - 48

Divide both sides by

4

(x + 1)^{2} = - 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 12 : x = 23 i - 1

Solve

x + 1 = - - 12 : x = - 23 i - 1

The solutions to the quadratic equation are:

x = 23 i - 1, x = - 23 i - 1

2 \cdot x^{2} - x - 2 = 0

x^{2} - 11 x - 46 = - 6 x + 4

x, x^{2} y - x^{2} + x y + 3 x - 2 = 0

6 x^{2} + x + 12 = 0

x^{2} = 9 x + 6

What are the solutions to the equation 4/3 (x+1)^2+16=0 ?
The solutions to the equation 4/3 (x+1)^2+16=0 are x=2sqrt(3)i-1,x=-2sqrt(3)i-1
Find the zeros of 4/3 (x+1)^2+16=0
The zeros of 4/3 (x+1)^2+16=0 are x=2sqrt(3)i-1,x=-2sqrt(3)i-1