What are the solutions to the equation M=(x+1)^2+(x-1)^2-2 ?

The solutions to the equation M=(x+1)^2+(x-1)^2-2 are x=sqrt(M/2),x=-sqrt(M/2)

Find the zeros of M=(x+1)^2+(x-1)^2-2

The zeros of M=(x+1)^2+(x-1)^2-2 are x=sqrt(M/2),x=-sqrt(M/2)

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M = (x + 1)^{2} + (x - 1)^{2} - 2

x = \frac{M}{2}, x = - \frac{M}{2}

Solution steps

M = (x + 1)^{2} + (x - 1)^{2} - 2

Expand

(x + 1)^{2} + (x - 1)^{2} - 2 : 2 x^{2}

M = 2 x^{2}

Switch sides

2 x^{2} = M

Move

M

to the left side

2 x^{2} - M = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 ( - M )}{2 \cdot 2}

Simplify

0^{2} - 4 \cdot 2 (- M) : 22 M

x_{1, 2} = \frac{- 0 \pm 2 2 M}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 2 2 M}{2 \cdot 2}, x_{2} = \frac{- 0 - 2 2 M}{2 \cdot 2}

x = \frac{- 0 + 2 2 M}{2 \cdot 2} : \frac{M}{2}

x = \frac{- 0 - 2 2 M}{2 \cdot 2} : - \frac{M}{2}

The solutions to the quadratic equation are:

x = \frac{M}{2}, x = - \frac{M}{2}

x, y = 4 - \frac{( x - 2 ) ^{2}}{4}

x, 4 x^{2} + 36 y^{2} + 9 z^{2} - 1 = 0

8 x^{2} + 3 x = 4 x^{2} - x

(3 - 2 x) (x + 3) = 7 + x (x + 2)

(x - 7) (2 x + 1) = 0

What are the solutions to the equation M=(x+1)^2+(x-1)^2-2 ?
The solutions to the equation M=(x+1)^2+(x-1)^2-2 are x=sqrt(M/2),x=-sqrt(M/2)
Find the zeros of M=(x+1)^2+(x-1)^2-2
The zeros of M=(x+1)^2+(x-1)^2-2 are x=sqrt(M/2),x=-sqrt(M/2)