What are the solutions to the equation -x^2-13x+30=0 ?

The solutions to the equation -x^2-13x+30=0 are x=-15,x=2

Find the zeros of -x^2-13x+30=0

The zeros of -x^2-13x+30=0 are x=-15,x=2

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- x^{2} - 13 x + 30 = 0

x = - 15, x = 2

Solution steps

- x^{2} - 13 x + 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 ( - 1 ) \cdot 30}{2 ( - 1 )}

(- 13)^{2} - 4 (- 1) \cdot 30 = 17

x_{1, 2} = \frac{- ( - 13 ) \pm 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 17}{2 ( - 1 )}, x_{2} = \frac{- ( - 13 ) - 17}{2 ( - 1 )}

x = \frac{- ( - 13 ) + 17}{2 ( - 1 )} : - 15

x = \frac{- ( - 13 ) - 17}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 15, x = 2

5 y^{2} = 6 y

0 = 2 x^{2} + 3 x - 10

x, 4 x^{2} + y^{2} - 4 z^{2} = 4

4 m^{2} + 17 m + 15 = m

x, 2 x^{2} + 4 x + 5 y + 6 z + 10 = 0

What are the solutions to the equation -x^2-13x+30=0 ?
The solutions to the equation -x^2-13x+30=0 are x=-15,x=2
Find the zeros of -x^2-13x+30=0
The zeros of -x^2-13x+30=0 are x=-15,x=2