What are the solutions to the equation completesquare-3y^2-4y ?

The solutions to the equation completesquare-3y^2-4y are -3(y+2/3)^2+4/3

Find the zeros of completesquare-3y^2-4y

The zeros of completesquare-3y^2-4y are -3(y+2/3)^2+4/3

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complete the square

- 3 y^{2} - 4 y

- 3 (y + \frac{2}{3})^{2} + \frac{4}{3}

Solution steps

- 3 y^{2} - 4 y

Write

- 3 y^{2} - 4 y

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 3

- 3 (y^{2} + \frac{4 y}{3})

2 a = \frac{4}{3} : a = \frac{2}{3}

Add and subtract

(\frac{2}{3})^{2}

- 3 (y^{2} + \frac{4 y}{3} + (\frac{2}{3})^{2} - (\frac{2}{3})^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

y^{2} + \frac{4}{3} y + (\frac{2}{3})^{2} = (y + \frac{2}{3})^{2}

- 3 ((y + \frac{2}{3})^{2} - (\frac{2}{3})^{2})

Simplify

- 3 (y + \frac{2}{3})^{2} + \frac{4}{3}

3 p (p + 3) = p - 3

46 x^{2} + 110 x - 404 = 0

- 3 x^{2} - 63 = 0

10 t^{2} + 21 t + 6 = 2 t

5 x^{2} + 35 = - 5

What are the solutions to the equation completesquare-3y^2-4y ?
The solutions to the equation completesquare-3y^2-4y are -3(y+2/3)^2+4/3
Find the zeros of completesquare-3y^2-4y
The zeros of completesquare-3y^2-4y are -3(y+2/3)^2+4/3