What is the answer to (2x-5)+(x+2)+(x+2)=19 ?

The answer to (2x-5)+(x+2)+(x+2)=19 is x=5

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(2x-5)+(x+2)+(x+2)=19

(2 x - 5) + (x + 2) + (x + 2) = 19

x = 5

Solution steps

(2 x - 5) + (x + 2) + (x + 2) = 19

Remove parentheses:

(a) = a

2 x - 5 + x + 2 + x + 2 = 19

Group like terms

2 x + x + x - 5 + 2 + 2 = 19

Add similar elements:

2 x + x + x = 4 x

4 x - 5 + 2 + 2 = 19

Add/Subtract the numbers:

- 5 + 2 + 2 = - 1

4 x - 1 = 19

Move

1

to the right side

4 x = 20

Divide both sides by

4

x = 5

∣ a ∣ = 8

0^{2}

n^{2} - 7 n - 8

7^{2} + 1 4^{2} = x^{2}

- 6 w + 1 = - 1

What is the answer to (2x-5)+(x+2)+(x+2)=19 ?
The answer to (2x-5)+(x+2)+(x+2)=19 is x=5
Solve for x: (2x-5)+(x+2)+(x+2)=19
The solution is x=5