What are the solutions to the equation 2v^2+13v+17=0 ?

The solutions to the equation 2v^2+13v+17=0 are v=(-13+sqrt(33))/4 ,v=(-13-sqrt(33))/4

Find the zeros of 2v^2+13v+17=0

The zeros of 2v^2+13v+17=0 are v=(-13+sqrt(33))/4 ,v=(-13-sqrt(33))/4

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2 v^{2} + 13 v + 17 = 0

v = \frac{- 13 + 33}{4}, v = \frac{- 13 - 33}{4}

Decimal Notation

v = - 1.81385 \dots, v = - 4.68614 \dots

Solution steps

2 v^{2} + 13 v + 17 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 \cdot 17}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 \cdot 17 = 33

v_{1, 2} = \frac{- 13 \pm 33}{2 \cdot 2}

Separate the solutions

v_{1} = \frac{- 13 + 33}{2 \cdot 2}, v_{2} = \frac{- 13 - 33}{2 \cdot 2}

v = \frac{- 13 + 33}{2 \cdot 2} : \frac{- 13 + 33}{4}

v = \frac{- 13 - 33}{2 \cdot 2} : \frac{- 13 - 33}{4}

The solutions to the quadratic equation are:

v = \frac{- 13 + 33}{4}, v = \frac{- 13 - 33}{4}

x^{2} - 13 x = - 7 x + 40

4 x^{2} - 780 x + 2304 = 0

x^{2} - 3 x + (- 9) = 12

2 x^{2} - 90 = 8

2 x^{2} + 4 x + 9

What are the solutions to the equation 2v^2+13v+17=0 ?
The solutions to the equation 2v^2+13v+17=0 are v=(-13+sqrt(33))/4 ,v=(-13-sqrt(33))/4
Find the zeros of 2v^2+13v+17=0
The zeros of 2v^2+13v+17=0 are v=(-13+sqrt(33))/4 ,v=(-13-sqrt(33))/4