What are the solutions to the equation x^2+(9/8)^2=1 ?

The solutions to the equation x^2+(9/8)^2=1 are x=(sqrt(17))/8 i,x=-(sqrt(17))/8 i

Find the zeros of x^2+(9/8)^2=1

The zeros of x^2+(9/8)^2=1 are x=(sqrt(17))/8 i,x=-(sqrt(17))/8 i

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x^{2} + (\frac{9}{8})^{2} = 1

x = \frac{17}{8} i, x = - \frac{17}{8} i

Solution steps

x^{2} + (\frac{9}{8})^{2} = 1

Expand

x^{2} + (\frac{9}{8})^{2} : x^{2} + \frac{81}{64}

x^{2} + \frac{81}{64} = 1

Move

\frac{81}{64}

to the right side

x^{2} = 1 - \frac{81}{64}

Simplify

1 - \frac{81}{64} : - \frac{17}{64}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{17}{64}, x = - - \frac{17}{64}

- \frac{17}{64} = \frac{17}{8} i

- - \frac{17}{64} = - \frac{17}{8} i

x = \frac{17}{8} i, x = - \frac{17}{8} i

a, a^{2} + ab - 2 a - 2 b = 0

4 m^{2} + 20 m + 25 = 0

x^{2} - 13 x + 6.25 = 0

x^{2} + 8 x + 76 = - 10 x - 4

(x - 1)^{2} = x (2 x - 1)

What are the solutions to the equation x^2+(9/8)^2=1 ?
The solutions to the equation x^2+(9/8)^2=1 are x=(sqrt(17))/8 i,x=-(sqrt(17))/8 i
Find the zeros of x^2+(9/8)^2=1
The zeros of x^2+(9/8)^2=1 are x=(sqrt(17))/8 i,x=-(sqrt(17))/8 i