What are the solutions to the equation 6x^2-23x=20 ?

The solutions to the equation 6x^2-23x=20 are x=(23+sqrt(1009))/(12),x=(23-sqrt(1009))/(12)

Find the zeros of 6x^2-23x=20

The zeros of 6x^2-23x=20 are x=(23+sqrt(1009))/(12),x=(23-sqrt(1009))/(12)

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6 x^{2} - 23 x = 20

x = \frac{23 + 1009}{12}, x = \frac{23 - 1009}{12}

Decimal Notation

x = 4.56373 \dots, x = - 0.73039 \dots

Solution steps

6 x^{2} - 23 x = 20

Move

20

to the left side

6 x^{2} - 23 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 6 ( - 20 )}{2 \cdot 6}

(- 23)^{2} - 4 \cdot 6 (- 20) = 1009

x_{1, 2} = \frac{- ( - 23 ) \pm 1009}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 1009}{2 \cdot 6}, x_{2} = \frac{- ( - 23 ) - 1009}{2 \cdot 6}

x = \frac{- ( - 23 ) + 1009}{2 \cdot 6} : \frac{23 + 1009}{12}

x = \frac{- ( - 23 ) - 1009}{2 \cdot 6} : \frac{23 - 1009}{12}

The solutions to the quadratic equation are:

x = \frac{23 + 1009}{12}, x = \frac{23 - 1009}{12}

x^{2} - 2 x - 4 = - 2 x

x^{2} - 3 = 3 - x^{2}

x^{2} - 16 x = - 15

3 t^{2} - 5 t + 2 = 0

x^{2} - 14 x + 35 = - 10

What are the solutions to the equation 6x^2-23x=20 ?
The solutions to the equation 6x^2-23x=20 are x=(23+sqrt(1009))/(12),x=(23-sqrt(1009))/(12)
Find the zeros of 6x^2-23x=20
The zeros of 6x^2-23x=20 are x=(23+sqrt(1009))/(12),x=(23-sqrt(1009))/(12)