What are the solutions to the equation 0.2x^2+2x+15=0 ?

The solutions to the equation 0.2x^2+2x+15=0 are x=-5+5sqrt(2)i,x=-5-5sqrt(2)i

Find the zeros of 0.2x^2+2x+15=0

The zeros of 0.2x^2+2x+15=0 are x=-5+5sqrt(2)i,x=-5-5sqrt(2)i

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0.2 x^{2} + 2 x + 15 = 0

x = - 5 + 52 i, x = - 5 - 52 i

Solution steps

0.2 x^{2} + 2 x + 15 = 0

Multiply both sides by

10

2 x^{2} + 20 x + 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 \cdot 150}{2 \cdot 2}

Simplify

2 0^{2} - 4 \cdot 2 \cdot 150 : 202 i

x_{1, 2} = \frac{- 20 \pm 20 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 20 2 i}{2 \cdot 2}, x_{2} = \frac{- 20 - 20 2 i}{2 \cdot 2}

x = \frac{- 20 + 20 2 i}{2 \cdot 2} : - 5 + 52 i

x = \frac{- 20 - 20 2 i}{2 \cdot 2} : - 5 - 52 i

The solutions to the quadratic equation are:

x = - 5 + 52 i, x = - 5 - 52 i

a, v = \frac{1}{3} a^{2} h

- 37 q + 827 = 0.32 q^{2} + 200

3 x = 2 x^{2} - 2

- 7 y^{2} + 16 y = 8 y

(2 a + 1) x^{2} + (- 5 a - 10) x + (3 a - 1) = 0

What are the solutions to the equation 0.2x^2+2x+15=0 ?
The solutions to the equation 0.2x^2+2x+15=0 are x=-5+5sqrt(2)i,x=-5-5sqrt(2)i
Find the zeros of 0.2x^2+2x+15=0
The zeros of 0.2x^2+2x+15=0 are x=-5+5sqrt(2)i,x=-5-5sqrt(2)i