What are the solutions to the equation 4x^2+3x=0 ?

The solutions to the equation 4x^2+3x=0 are x=0,x=-3/4

Find the zeros of 4x^2+3x=0

The zeros of 4x^2+3x=0 are x=0,x=-3/4

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4 x^{2} + 3 x = 0

x = 0, x = - \frac{3}{4}

Decimal Notation

x = 0, x = - 0.75

Solution steps

4 x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

3^{2} - 4 \cdot 4 \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 \cdot 4}, x_{2} = \frac{- 3 - 3}{2 \cdot 4}

x = \frac{- 3 + 3}{2 \cdot 4} : 0

x = \frac{- 3 - 3}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{3}{4}

\frac{5}{2} w - 11 > - 31

lo g_{5} (157) = x + 2

(x + 3) (x - 4) \geq 0

\frac{2 y}{3} - \frac{y + 3}{6} = 2

0 = x^{2} - 7 x + 12

What are the solutions to the equation 4x^2+3x=0 ?
The solutions to the equation 4x^2+3x=0 are x=0,x=-3/4
Find the zeros of 4x^2+3x=0
The zeros of 4x^2+3x=0 are x=0,x=-3/4