What are the solutions to the equation 2k^2+5k-11=1 ?

The solutions to the equation 2k^2+5k-11=1 are k= 3/2 ,k=-4

Find the zeros of 2k^2+5k-11=1

The zeros of 2k^2+5k-11=1 are k= 3/2 ,k=-4

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2 k^{2} + 5 k - 11 = 1

k = \frac{3}{2}, k = - 4

Decimal Notation

k = 1.5, k = - 4

Solution steps

2 k^{2} + 5 k - 11 = 1

Move

1

to the left side

2 k^{2} + 5 k - 12 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 12) = 11

k_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 5 + 11}{2 \cdot 2}, k_{2} = \frac{- 5 - 11}{2 \cdot 2}

k = \frac{- 5 + 11}{2 \cdot 2} : \frac{3}{2}

k = \frac{- 5 - 11}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

k = \frac{3}{2}, k = - 4

9 k^{2} - 27 k + 20 = 0

15 a^{2} - 8 a - 3 = - 4

x^{2} - 4 = 4 - x^{2}

6 k^{2} + 6 k - 6 = k

(x - 2) (2 x + 3) = 0

What are the solutions to the equation 2k^2+5k-11=1 ?
The solutions to the equation 2k^2+5k-11=1 are k= 3/2 ,k=-4
Find the zeros of 2k^2+5k-11=1
The zeros of 2k^2+5k-11=1 are k= 3/2 ,k=-4