What are the solutions to the equation -2x^2+60x-120=0 ?

The solutions to the equation -2x^2+60x-120=0 are x=15-sqrt(165),x=15+sqrt(165)

Find the zeros of -2x^2+60x-120=0

The zeros of -2x^2+60x-120=0 are x=15-sqrt(165),x=15+sqrt(165)

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- 2 x^{2} + 60 x - 120 = 0

x = 15 - 165, x = 15 + 165

Decimal Notation

x = 2.15476 \dots, x = 27.84523 \dots

Solution steps

- 2 x^{2} + 60 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 ( - 2 ) ( - 120 )}{2 ( - 2 )}

6 0^{2} - 4 (- 2) (- 120) = 4165

x_{1, 2} = \frac{- 60 \pm 4 165}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 60 + 4 165}{2 ( - 2 )}, x_{2} = \frac{- 60 - 4 165}{2 ( - 2 )}

x = \frac{- 60 + 4 165}{2 ( - 2 )} : 15 - 165

x = \frac{- 60 - 4 165}{2 ( - 2 )} : 15 + 165

The solutions to the quadratic equation are:

x = 15 - 165, x = 15 + 165

3 n^{2} + 17 n + 17 = - 2

x, 2 x^{2} + y^{2} - x + 3 y + 6 = 0

- x^{2} + 3 = x^{2} - 2 x - 1

x^{2} - 5 x - 12 = - 5 x + 4

3 x (x - 2) + 4 = 6

What are the solutions to the equation -2x^2+60x-120=0 ?
The solutions to the equation -2x^2+60x-120=0 are x=15-sqrt(165),x=15+sqrt(165)
Find the zeros of -2x^2+60x-120=0
The zeros of -2x^2+60x-120=0 are x=15-sqrt(165),x=15+sqrt(165)