What are the solutions to the equation x^2+24=10 ?

The solutions to the equation x^2+24=10 are x=sqrt(14)i,x=-sqrt(14)i

Find the zeros of x^2+24=10

The zeros of x^2+24=10 are x=sqrt(14)i,x=-sqrt(14)i

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x^{2} + 24 = 10

x = 14 i, x = - 14 i

Solution steps

x^{2} + 24 = 10

Move

24

to the right side

x^{2} = - 14

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 14, x = - - 14

- 14 = 14 i

- - 14 = - 14 i

x = 14 i, x = - 14 i

(x + 1) (2 x - 3) = 0

x^{2} - 20 x + 36 = - 7 x

x^{2} - 16 x + 38 = - 3 x - 2

x^{2} - 8 x - 6 = - 6

y, y^{2} = \frac{17}{8} x^{2} (4 - x)

What are the solutions to the equation x^2+24=10 ?
The solutions to the equation x^2+24=10 are x=sqrt(14)i,x=-sqrt(14)i
Find the zeros of x^2+24=10
The zeros of x^2+24=10 are x=sqrt(14)i,x=-sqrt(14)i