What are the solutions to the equation x^2+2x-76=4 ?

The solutions to the equation x^2+2x-76=4 are x=8,x=-10

Find the zeros of x^2+2x-76=4

The zeros of x^2+2x-76=4 are x=8,x=-10

Popular >

x^{2} + 2 x - 76 = 4

x = 8, x = - 10

Solution steps

x^{2} + 2 x - 76 = 4

Move

4

to the left side

x^{2} + 2 x - 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 80 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 80) = 18

x_{1, 2} = \frac{- 2 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 18}{2 \cdot 1}, x_{2} = \frac{- 2 - 18}{2 \cdot 1}

x = \frac{- 2 + 18}{2 \cdot 1} : 8

x = \frac{- 2 - 18}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 8, x = - 10

(x - 3)^{2} = 2 x (x - 4) - 15

xx - 4 x - 4 = 0

3 (5 x^{2} - 3 x + 2) = 2 (3 x^{2} - x + 3)

x^{2} - 8 x + 16 = 2

x, y^{5} (x^{2} - 1) + 2 x + 5 y = x^{2} - 2 y^{4}

What are the solutions to the equation x^2+2x-76=4 ?
The solutions to the equation x^2+2x-76=4 are x=8,x=-10
Find the zeros of x^2+2x-76=4
The zeros of x^2+2x-76=4 are x=8,x=-10