What are the solutions to the equation (4-3x)^2=64 ?

The solutions to the equation (4-3x)^2=64 are x=-4/3 ,x=4

Find the zeros of (4-3x)^2=64

The zeros of (4-3x)^2=64 are x=-4/3 ,x=4

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(4 - 3 x)^{2} = 64

x = - \frac{4}{3}, x = 4

Decimal Notation

x = - 1.33333 \dots, x = 4

Solution steps

(4 - 3 x)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 - 3 x = 64 : x = - \frac{4}{3}

Solve

4 - 3 x = - 64 : x = 4

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = 4

x^{2} + 12 x + c = 0

12 = 3 x^{2} - 18 x

(- \frac{13}{3} x)^{2} + (- \frac{2}{3} x)^{2} + x^{2} = 1

2 x^{2} + 6 x - 196 = 0

4 m^{2} - 8 m + 9 = 0

What are the solutions to the equation (4-3x)^2=64 ?
The solutions to the equation (4-3x)^2=64 are x=-4/3 ,x=4
Find the zeros of (4-3x)^2=64
The zeros of (4-3x)^2=64 are x=-4/3 ,x=4