What are the solutions to the equation 5n^2-20n+25=n^2 ?

The solutions to the equation 5n^2-20n+25=n^2 are n= 5/2

Find the zeros of 5n^2-20n+25=n^2

The zeros of 5n^2-20n+25=n^2 are n= 5/2

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5 n^{2} - 20 n + 25 = n^{2}

n = \frac{5}{2}

Decimal Notation

n = 2.5

Solution steps

5 n^{2} - 20 n + 25 = n^{2}

Move

n^{2}

to the left side

4 n^{2} - 20 n + 25 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

n_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

n = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

n = \frac{5}{2}

The solution to the quadratic equation is:

n = \frac{5}{2}

12 x^{2} - 3 x + 2 = 0

2 c^{2} - 9 c + 5 = 2 c

6 n^{2} + 10 n + 25 = 5 n^{2}

4 y^{2} - 8 y - 10 = - 5

x^{2} + 10 x = - 4 x - 40

What are the solutions to the equation 5n^2-20n+25=n^2 ?
The solutions to the equation 5n^2-20n+25=n^2 are n= 5/2
Find the zeros of 5n^2-20n+25=n^2
The zeros of 5n^2-20n+25=n^2 are n= 5/2