What are the solutions to the equation (9x+4)^2=72x+25 ?

The solutions to the equation (9x+4)^2=72x+25 are x= 1/3 ,x=-1/3

Find the zeros of (9x+4)^2=72x+25

The zeros of (9x+4)^2=72x+25 are x= 1/3 ,x=-1/3

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(9 x + 4)^{2} = 72 x + 25

x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.33333 \dots, x = - 0.33333 \dots

Solution steps

(9 x + 4)^{2} = 72 x + 25

Expand

(9 x + 4)^{2} : 81 x^{2} + 72 x + 16

81 x^{2} + 72 x + 16 = 72 x + 25

Move

16

to the right side

81 x^{2} + 72 x = 72 x + 9

Move

72 x

to the left side

81 x^{2} = 9

Divide both sides by

81

x^{2} = \frac{1}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{9}, x = - \frac{1}{9}

\frac{1}{9} = \frac{1}{3}

- \frac{1}{9} = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

5529 x^{2} - 18634 x + 8841 = 0

25 n^{2} - 15 n + 4 = 5 n

3 x^{2} + 1 = 7 x - 3

x^{2} - 8 x + 16 = 2

x^{2} + 3 x = - 4 x

What are the solutions to the equation (9x+4)^2=72x+25 ?
The solutions to the equation (9x+4)^2=72x+25 are x= 1/3 ,x=-1/3
Find the zeros of (9x+4)^2=72x+25
The zeros of (9x+4)^2=72x+25 are x= 1/3 ,x=-1/3