What are the solutions to the equation c^2+4c+4=0 ?

The solutions to the equation c^2+4c+4=0 are c=-2

Find the zeros of c^2+4c+4=0

The zeros of c^2+4c+4=0 are c=-2

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c^{2} + 4 c + 4 = 0

c = - 2

Solution steps

c^{2} + 4 c + 4 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

c_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

c = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

c = - 2

The solution to the quadratic equation is:

c = - 2

12 n^{2} + 12 n + 9 = 0

x, 16 x^{2} + 9 y^{2} + 16 z^{2} - 32 x - 36 y + 36 = 0

3 X^{2} - 2 X + 4 = 0

3 x^{2} + 17 = 14 x + 9

y, y^{2} = 6 x^{4} - x^{5}

What are the solutions to the equation c^2+4c+4=0 ?
The solutions to the equation c^2+4c+4=0 are c=-2
Find the zeros of c^2+4c+4=0
The zeros of c^2+4c+4=0 are c=-2