What are the solutions to the equation -3x^2+6x+3=0 ?

The solutions to the equation -3x^2+6x+3=0 are x=1-sqrt(2),x=1+sqrt(2)

Find the zeros of -3x^2+6x+3=0

The zeros of -3x^2+6x+3=0 are x=1-sqrt(2),x=1+sqrt(2)

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- 3 x^{2} + 6 x + 3 = 0

x = 1 - 2, x = 1 + 2

Decimal Notation

x = - 0.41421 \dots, x = 2.41421 \dots

Solution steps

- 3 x^{2} + 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 3}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 3 = 62

x_{1, 2} = \frac{- 6 \pm 6 2}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 6 2}{2 ( - 3 )}, x_{2} = \frac{- 6 - 6 2}{2 ( - 3 )}

x = \frac{- 6 + 6 2}{2 ( - 3 )} : 1 - 2

x = \frac{- 6 - 6 2}{2 ( - 3 )} : 1 + 2

The solutions to the quadratic equation are:

x = 1 - 2, x = 1 + 2

x + 3 \leq - 6

3 x^{2} + 5 x - 8

f = 19 + 6 (2)

8 + 2 ∣ 9 m - 2 ∣ = - 14

(x + 2)^{3} - 8 (x - 1)^{3}

What are the solutions to the equation -3x^2+6x+3=0 ?
The solutions to the equation -3x^2+6x+3=0 are x=1-sqrt(2),x=1+sqrt(2)
Find the zeros of -3x^2+6x+3=0
The zeros of -3x^2+6x+3=0 are x=1-sqrt(2),x=1+sqrt(2)