What are the solutions to the equation -p^2+5p+6=-2p^2 ?

The solutions to the equation -p^2+5p+6=-2p^2 are p=-2,p=-3

Find the zeros of -p^2+5p+6=-2p^2

The zeros of -p^2+5p+6=-2p^2 are p=-2,p=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- p^{2} + 5 p + 6 = - 2 p^{2}

p = - 2, p = - 3

Solution steps

- p^{2} + 5 p + 6 = - 2 p^{2}

Move

2 p^{2}

to the left side

p^{2} + 5 p + 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

p_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 5 + 1}{2 \cdot 1}, p_{2} = \frac{- 5 - 1}{2 \cdot 1}

p = \frac{- 5 + 1}{2 \cdot 1} : - 2

p = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

p = - 2, p = - 3

(x - 64) (x + 64) = 0

x, 2 x^{2} + y^{2} = 4 C x

- 12 x^{2} + 11 x - 2 = 0

x, - x^{2} + y^{2} - z^{2} = 1

\frac{x}{2} - \frac{x ^{2}}{4} = 0

What are the solutions to the equation -p^2+5p+6=-2p^2 ?
The solutions to the equation -p^2+5p+6=-2p^2 are p=-2,p=-3
Find the zeros of -p^2+5p+6=-2p^2
The zeros of -p^2+5p+6=-2p^2 are p=-2,p=-3