What are the solutions to the equation c^2+9c+12=-4 ?

The solutions to the equation c^2+9c+12=-4 are c=(-9+sqrt(17))/2 ,c=(-9-sqrt(17))/2

Find the zeros of c^2+9c+12=-4

The zeros of c^2+9c+12=-4 are c=(-9+sqrt(17))/2 ,c=(-9-sqrt(17))/2

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c^{2} + 9 c + 12 = - 4

c = \frac{- 9 + 17}{2}, c = \frac{- 9 - 17}{2}

Decimal Notation

c = - 2.43844 \dots, c = - 6.56155 \dots

Solution steps

c^{2} + 9 c + 12 = - 4

Move

4

to the left side

c^{2} + 9 c + 16 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 16 = 17

c_{1, 2} = \frac{- 9 \pm 17}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 9 + 17}{2 \cdot 1}, c_{2} = \frac{- 9 - 17}{2 \cdot 1}

c = \frac{- 9 + 17}{2 \cdot 1} : \frac{- 9 + 17}{2}

c = \frac{- 9 - 17}{2 \cdot 1} : \frac{- 9 - 17}{2}

The solutions to the quadratic equation are:

c = \frac{- 9 + 17}{2}, c = \frac{- 9 - 17}{2}

2 x (x + 3) = 6 x + 4

22 p^{2} + 16 p - 5 = 6 p^{2}

x^{2} - 3 x + \frac{9}{4} = 12

x^{2} - 8 x = 3 x

32 x^{2} - 2 = 0

What are the solutions to the equation c^2+9c+12=-4 ?
The solutions to the equation c^2+9c+12=-4 are c=(-9+sqrt(17))/2 ,c=(-9-sqrt(17))/2
Find the zeros of c^2+9c+12=-4
The zeros of c^2+9c+12=-4 are c=(-9+sqrt(17))/2 ,c=(-9-sqrt(17))/2