What are the solutions to the equation 3b^2-7b+3=6 ?

The solutions to the equation 3b^2-7b+3=6 are b=(7+sqrt(85))/6 ,b=(7-sqrt(85))/6

Find the zeros of 3b^2-7b+3=6

The zeros of 3b^2-7b+3=6 are b=(7+sqrt(85))/6 ,b=(7-sqrt(85))/6

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3 b^{2} - 7 b + 3 = 6

b = \frac{7 + 85}{6}, b = \frac{7 - 85}{6}

Decimal Notation

b = 2.70325 \dots, b = - 0.36992 \dots

Solution steps

3 b^{2} - 7 b + 3 = 6

Move

6

to the left side

3 b^{2} - 7 b - 3 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 3) = 85

b_{1, 2} = \frac{- ( - 7 ) \pm 85}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- ( - 7 ) + 85}{2 \cdot 3}, b_{2} = \frac{- ( - 7 ) - 85}{2 \cdot 3}

b = \frac{- ( - 7 ) + 85}{2 \cdot 3} : \frac{7 + 85}{6}

b = \frac{- ( - 7 ) - 85}{2 \cdot 3} : \frac{7 - 85}{6}

The solutions to the quadratic equation are:

b = \frac{7 + 85}{6}, b = \frac{7 - 85}{6}

a, (a + b + c + d)^{2} = 4 (a + b) (c + d)

x^{2} - 4 x - 24 = - 9 x

x^{2} - 3 x - 38 = - 10

\frac{4 x}{3} - \frac{1}{3} x (x - 1) = x^{2} + x

x^{2} + 12 x - 253 = 0

What are the solutions to the equation 3b^2-7b+3=6 ?
The solutions to the equation 3b^2-7b+3=6 are b=(7+sqrt(85))/6 ,b=(7-sqrt(85))/6
Find the zeros of 3b^2-7b+3=6
The zeros of 3b^2-7b+3=6 are b=(7+sqrt(85))/6 ,b=(7-sqrt(85))/6