What are the solutions to the equation q^2-q-10=2q ?

The solutions to the equation q^2-q-10=2q are q=5,q=-2

Find the zeros of q^2-q-10=2q

The zeros of q^2-q-10=2q are q=5,q=-2

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q^{2} - q - 10 = 2 q

q = 5, q = - 2

Solution steps

q^{2} - q - 10 = 2 q

Move

2 q

to the left side

q^{2} - 3 q - 10 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

q_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, q_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

q = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

q = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

q = 5, q = - 2

4 y^{2} + 11 y + 3 = - 1

v, \frac{m v ^{2}}{r} = q v B

5 x^{2} + 14 x = x + 6

x, x^{2} (y^{2} - 4) = 4

x, 4 y^{2} + 10 x^{2} - 2 y + 5 = 0

What are the solutions to the equation q^2-q-10=2q ?
The solutions to the equation q^2-q-10=2q are q=5,q=-2
Find the zeros of q^2-q-10=2q
The zeros of q^2-q-10=2q are q=5,q=-2