What are the solutions to the equation 4x^2+48x-25=0 ?

The solutions to the equation 4x^2+48x-25=0 are x= 1/2 ,x=-25/2

Find the zeros of 4x^2+48x-25=0

The zeros of 4x^2+48x-25=0 are x= 1/2 ,x=-25/2

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4 x^{2} + 48 x - 25 = 0

x = \frac{1}{2}, x = - \frac{25}{2}

Decimal Notation

x = 0.5, x = - 12.5

Solution steps

4 x^{2} + 48 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 4 ( - 25 )}{2 \cdot 4}

4 8^{2} - 4 \cdot 4 (- 25) = 52

x_{1, 2} = \frac{- 48 \pm 52}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 48 + 52}{2 \cdot 4}, x_{2} = \frac{- 48 - 52}{2 \cdot 4}

x = \frac{- 48 + 52}{2 \cdot 4} : \frac{1}{2}

x = \frac{- 48 - 52}{2 \cdot 4} : - \frac{25}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{25}{2}

x^{2} - \frac{5}{2} x - \frac{39}{16} = 0

x, x^{2} + z^{2} + 4 - y^{2} = 4

2 x^{2} + 5 x = 8

2 x^{2} - 11 x + 14 = 0

3504.572919 = - 0.1037 \cdot x^{2} + 24.301 \cdot x + 284.51

What are the solutions to the equation 4x^2+48x-25=0 ?
The solutions to the equation 4x^2+48x-25=0 are x= 1/2 ,x=-25/2
Find the zeros of 4x^2+48x-25=0
The zeros of 4x^2+48x-25=0 are x= 1/2 ,x=-25/2