What are the solutions to the equation 2a^2+a-23=-2 ?

The solutions to the equation 2a^2+a-23=-2 are a=3,a=-7/2

Find the zeros of 2a^2+a-23=-2

The zeros of 2a^2+a-23=-2 are a=3,a=-7/2

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2 a^{2} + a - 23 = - 2

a = 3, a = - \frac{7}{2}

Decimal Notation

a = 3, a = - 3.5

Solution steps

2 a^{2} + a - 23 = - 2

Move

2

to the left side

2 a^{2} + a - 21 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 21) = 13

a_{1, 2} = \frac{- 1 \pm 13}{2 \cdot 2}

Separate the solutions

a_{1} = \frac{- 1 + 13}{2 \cdot 2}, a_{2} = \frac{- 1 - 13}{2 \cdot 2}

a = \frac{- 1 + 13}{2 \cdot 2} : 3

a = \frac{- 1 - 13}{2 \cdot 2} : - \frac{7}{2}

The solutions to the quadratic equation are:

a = 3, a = - \frac{7}{2}

4 = - x^{2} + x + 6

x, x^{2} + y^{2} + z^{2} = a^{2}

x^{2} - 9 x - 136 = 0

x^{2} - \frac{1}{2} x - 2 = 0

x, x y^{2} - 2 x^{2} y = 4

What are the solutions to the equation 2a^2+a-23=-2 ?
The solutions to the equation 2a^2+a-23=-2 are a=3,a=-7/2
Find the zeros of 2a^2+a-23=-2
The zeros of 2a^2+a-23=-2 are a=3,a=-7/2