What are the solutions to the equation 8q^2+8q-4=3q^2 ?

The solutions to the equation 8q^2+8q-4=3q^2 are q= 2/5 ,q=-2

Find the zeros of 8q^2+8q-4=3q^2

The zeros of 8q^2+8q-4=3q^2 are q= 2/5 ,q=-2

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8 q^{2} + 8 q - 4 = 3 q^{2}

q = \frac{2}{5}, q = - 2

Decimal Notation

q = 0.4, q = - 2

Solution steps

8 q^{2} + 8 q - 4 = 3 q^{2}

Move

3 q^{2}

to the left side

5 q^{2} + 8 q - 4 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

8^{2} - 4 \cdot 5 (- 4) = 12

q_{1, 2} = \frac{- 8 \pm 12}{2 \cdot 5}

Separate the solutions

q_{1} = \frac{- 8 + 12}{2 \cdot 5}, q_{2} = \frac{- 8 - 12}{2 \cdot 5}

q = \frac{- 8 + 12}{2 \cdot 5} : \frac{2}{5}

q = \frac{- 8 - 12}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

q = \frac{2}{5}, q = - 2

d^{2} - 2 d - 4 = 0

x, x^{2} - k x + 1 = 0

3 x^{2} - 8 x - 10 = 4

3 x^{2} + 3 x - 9 = 4 x - 7

3 b^{2} + 9 b - 20 = 2 b

What are the solutions to the equation 8q^2+8q-4=3q^2 ?
The solutions to the equation 8q^2+8q-4=3q^2 are q= 2/5 ,q=-2
Find the zeros of 8q^2+8q-4=3q^2
The zeros of 8q^2+8q-4=3q^2 are q= 2/5 ,q=-2