What are the solutions to the equation 6a^2+7a-11=5a^2 ?

The solutions to the equation 6a^2+7a-11=5a^2 are a=(-7+sqrt(93))/2 ,a=(-7-sqrt(93))/2

Find the zeros of 6a^2+7a-11=5a^2

The zeros of 6a^2+7a-11=5a^2 are a=(-7+sqrt(93))/2 ,a=(-7-sqrt(93))/2

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6 a^{2} + 7 a - 11 = 5 a^{2}

a = \frac{- 7 + 93}{2}, a = \frac{- 7 - 93}{2}

Decimal Notation

a = 1.32182 \dots, a = - 8.32182 \dots

Solution steps

6 a^{2} + 7 a - 11 = 5 a^{2}

Move

5 a^{2}

to the left side

a^{2} + 7 a - 11 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 11) = 93

a_{1, 2} = \frac{- 7 \pm 93}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 7 + 93}{2 \cdot 1}, a_{2} = \frac{- 7 - 93}{2 \cdot 1}

a = \frac{- 7 + 93}{2 \cdot 1} : \frac{- 7 + 93}{2}

a = \frac{- 7 - 93}{2 \cdot 1} : \frac{- 7 - 93}{2}

The solutions to the quadratic equation are:

a = \frac{- 7 + 93}{2}, a = \frac{- 7 - 93}{2}

18 x^{2} - 27 x + 4 = 0

7 x^{2} - 2 = - 5 x

6 x^{2} - 2 = 13

11 a^{2} - 11 a + 3 = 6 a^{2}

d^{2} + 11 d + 16 = 0

What are the solutions to the equation 6a^2+7a-11=5a^2 ?
The solutions to the equation 6a^2+7a-11=5a^2 are a=(-7+sqrt(93))/2 ,a=(-7-sqrt(93))/2
Find the zeros of 6a^2+7a-11=5a^2
The zeros of 6a^2+7a-11=5a^2 are a=(-7+sqrt(93))/2 ,a=(-7-sqrt(93))/2