What are the solutions to the equation 15d^2-29d+8=-4 ?

The solutions to the equation 15d^2-29d+8=-4 are d= 4/3 ,d= 3/5

Find the zeros of 15d^2-29d+8=-4

The zeros of 15d^2-29d+8=-4 are d= 4/3 ,d= 3/5

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15 d^{2} - 29 d + 8 = - 4

d = \frac{4}{3}, d = \frac{3}{5}

Decimal Notation

d = 1.33333 \dots, d = 0.6

Solution steps

15 d^{2} - 29 d + 8 = - 4

Move

4

to the left side

15 d^{2} - 29 d + 12 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 15 \cdot 12}{2 \cdot 15}

(- 29)^{2} - 4 \cdot 15 \cdot 12 = 11

d_{1, 2} = \frac{- ( - 29 ) \pm 11}{2 \cdot 15}

Separate the solutions

d_{1} = \frac{- ( - 29 ) + 11}{2 \cdot 15}, d_{2} = \frac{- ( - 29 ) - 11}{2 \cdot 15}

d = \frac{- ( - 29 ) + 11}{2 \cdot 15} : \frac{4}{3}

d = \frac{- ( - 29 ) - 11}{2 \cdot 15} : \frac{3}{5}

The solutions to the quadratic equation are:

d = \frac{4}{3}, d = \frac{3}{5}

x^{2} + 8 = - 1

x, 12 x^{2} - 3 y^{2} + 12 z^{2} + 6 x = 15

0.534 (0.5 - x)^{2} = x^{2}

x, z = x^{2} + x y + y^{2} - 3 x - 6 y

5 p^{2} - 7 p + 3 = p^{2}

What are the solutions to the equation 15d^2-29d+8=-4 ?
The solutions to the equation 15d^2-29d+8=-4 are d= 4/3 ,d= 3/5
Find the zeros of 15d^2-29d+8=-4
The zeros of 15d^2-29d+8=-4 are d= 4/3 ,d= 3/5