What are the solutions to the equation 6p^2-26p+5=p^2 ?

The solutions to the equation 6p^2-26p+5=p^2 are p=5,p= 1/5

Find the zeros of 6p^2-26p+5=p^2

The zeros of 6p^2-26p+5=p^2 are p=5,p= 1/5

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6 p^{2} - 26 p + 5 = p^{2}

p = 5, p = \frac{1}{5}

Decimal Notation

p = 5, p = 0.2

Solution steps

6 p^{2} - 26 p + 5 = p^{2}

Move

p^{2}

to the left side

5 p^{2} - 26 p + 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 5 \cdot 5}{2 \cdot 5}

(- 26)^{2} - 4 \cdot 5 \cdot 5 = 24

p_{1, 2} = \frac{- ( - 26 ) \pm 24}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- ( - 26 ) + 24}{2 \cdot 5}, p_{2} = \frac{- ( - 26 ) - 24}{2 \cdot 5}

p = \frac{- ( - 26 ) + 24}{2 \cdot 5} : 5

p = \frac{- ( - 26 ) - 24}{2 \cdot 5} : \frac{1}{5}

The solutions to the quadratic equation are:

p = 5, p = \frac{1}{5}

x^{2} + 6 x - 2 = 7 x + 10

3 x^{2} + 1 = - 13 x - 3

2 \cdot (5 x^{2} + 3) = 9 x^{2} + 3 x + 4

x^{2} + 10 = 7 x + 4

k^{2} - 4 k = 32

What are the solutions to the equation 6p^2-26p+5=p^2 ?
The solutions to the equation 6p^2-26p+5=p^2 are p=5,p= 1/5
Find the zeros of 6p^2-26p+5=p^2
The zeros of 6p^2-26p+5=p^2 are p=5,p= 1/5