What are the solutions to the equation (5x-3)^2=-32 ?

The solutions to the equation (5x-3)^2=-32 are x= 3/5+i(4sqrt(2))/5 ,x= 3/5-i(4sqrt(2))/5

Find the zeros of (5x-3)^2=-32

The zeros of (5x-3)^2=-32 are x= 3/5+i(4sqrt(2))/5 ,x= 3/5-i(4sqrt(2))/5

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(5 x - 3)^{2} = - 32

x = \frac{3}{5} + i \frac{4 2}{5}, x = \frac{3}{5} - i \frac{4 2}{5}

Solution steps

(5 x - 3)^{2} = - 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 3 = - 32 : x = \frac{3}{5} + i \frac{4 2}{5}

Solve

5 x - 3 = - - 32 : x = \frac{3}{5} - i \frac{4 2}{5}

The solutions to the quadratic equation are:

x = \frac{3}{5} + i \frac{4 2}{5}, x = \frac{3}{5} - i \frac{4 2}{5}

8 w^{2} - 14 w + 5 = 0

x^{2} + 3 n x + n + 1 = 0

2 x^{2} - 19 x + 24 = 0

x^{2} + 2 x + 5 = 4

- x^{2} - 6 x + 9 = 0

What are the solutions to the equation (5x-3)^2=-32 ?
The solutions to the equation (5x-3)^2=-32 are x= 3/5+i(4sqrt(2))/5 ,x= 3/5-i(4sqrt(2))/5
Find the zeros of (5x-3)^2=-32
The zeros of (5x-3)^2=-32 are x= 3/5+i(4sqrt(2))/5 ,x= 3/5-i(4sqrt(2))/5