What are the solutions to the equation 7=-x^2-9x ?

The solutions to the equation 7=-x^2-9x are x=-(9+sqrt(53))/2 ,x=-(9-sqrt(53))/2

Find the zeros of 7=-x^2-9x

The zeros of 7=-x^2-9x are x=-(9+sqrt(53))/2 ,x=-(9-sqrt(53))/2

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7 = - x^{2} - 9 x

x = - \frac{9 + 53}{2}, x = - \frac{9 - 53}{2}

Decimal Notation

x = - 8.14005 \dots, x = - 0.85994 \dots

Solution steps

7 = - x^{2} - 9 x

Switch sides

- x^{2} - 9 x = 7

Move

7

to the left side

- x^{2} - 9 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 1 ) ( - 7 )}{2 ( - 1 )}

(- 9)^{2} - 4 (- 1) (- 7) = 53

x_{1, 2} = \frac{- ( - 9 ) \pm 53}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 53}{2 ( - 1 )}, x_{2} = \frac{- ( - 9 ) - 53}{2 ( - 1 )}

x = \frac{- ( - 9 ) + 53}{2 ( - 1 )} : - \frac{9 + 53}{2}

x = \frac{- ( - 9 ) - 53}{2 ( - 1 )} : - \frac{9 - 53}{2}

The solutions to the quadratic equation are:

x = - \frac{9 + 53}{2}, x = - \frac{9 - 53}{2}

x^{2} - \frac{3}{4} x - \frac{27}{64} = 0

x, 9 x^{2} + y^{2} + 4 z^{2} - 18 x + 2 y + 16 z = 10

10 x^{2} = - 19 x + 15

p^{2} - 5 p - 5 = - 2 p

10 k^{2} + 21 k + 9 = 0

What are the solutions to the equation 7=-x^2-9x ?
The solutions to the equation 7=-x^2-9x are x=-(9+sqrt(53))/2 ,x=-(9-sqrt(53))/2
Find the zeros of 7=-x^2-9x
The zeros of 7=-x^2-9x are x=-(9+sqrt(53))/2 ,x=-(9-sqrt(53))/2