What are the solutions to the equation (m-2)(m+2)=0 ?

The solutions to the equation (m-2)(m+2)=0 are m=2,m=-2

Find the zeros of (m-2)(m+2)=0

The zeros of (m-2)(m+2)=0 are m=2,m=-2

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(m - 2) (m + 2) = 0

m = 2, m = - 2

Solution steps

(m - 2) (m + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m - 2 = 0 or m + 2 = 0

Solve

m - 2 = 0 : m = 2

Solve

m + 2 = 0 : m = - 2

The solutions to the quadratic equation are:

m = 2, m = - 2

25 = (x - 3)^{2}

(x - 64)^{2} = 0

200 - 2 x = 100 + 0.2 x^{2}

- 2 x (5 x - 2) = 0

x^{2} - 3 x - 9 = 12

What are the solutions to the equation (m-2)(m+2)=0 ?
The solutions to the equation (m-2)(m+2)=0 are m=2,m=-2
Find the zeros of (m-2)(m+2)=0
The zeros of (m-2)(m+2)=0 are m=2,m=-2