What are the solutions to the equation m^2-2m-39=7 ?

The solutions to the equation m^2-2m-39=7 are m=1+sqrt(47),m=1-sqrt(47)

Find the zeros of m^2-2m-39=7

The zeros of m^2-2m-39=7 are m=1+sqrt(47),m=1-sqrt(47)

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m^{2} - 2 m - 39 = 7

m = 1 + 47, m = 1 - 47

Decimal Notation

m = 7.85565 \dots, m = - 5.85565 \dots

Solution steps

m^{2} - 2 m - 39 = 7

Move

7

to the left side

m^{2} - 2 m - 46 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 46 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 46) = 247

m_{1, 2} = \frac{- ( - 2 ) \pm 2 47}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 47}{2 \cdot 1}, m_{2} = \frac{- ( - 2 ) - 2 47}{2 \cdot 1}

m = \frac{- ( - 2 ) + 2 47}{2 \cdot 1} : 1 + 47

m = \frac{- ( - 2 ) - 2 47}{2 \cdot 1} : 1 - 47

The solutions to the quadratic equation are:

m = 1 + 47, m = 1 - 47

30 s^{2} + 13 s - 10 = 0

90 = \frac{n ( n - 3 )}{2}

x^{2} - 6 x - 33 = - 4 x + 2

4 x^{2} + 6 x = 4

x - 2 x^{2} + 13 x - 21 = 0

What are the solutions to the equation m^2-2m-39=7 ?
The solutions to the equation m^2-2m-39=7 are m=1+sqrt(47),m=1-sqrt(47)
Find the zeros of m^2-2m-39=7
The zeros of m^2-2m-39=7 are m=1+sqrt(47),m=1-sqrt(47)