What are the solutions to the equation 0.1x^2-30x+2250=0 ?

The solutions to the equation 0.1x^2-30x+2250=0 are x=150

Find the zeros of 0.1x^2-30x+2250=0

The zeros of 0.1x^2-30x+2250=0 are x=150

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0.1 x^{2} - 30 x + 2250 = 0

x = 150

Solution steps

0.1 x^{2} - 30 x + 2250 = 0

Multiply both sides by

10

x^{2} - 300 x + 22500 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 300 ) \pm ( - 300 ) ^{2} - 4 \cdot 1 \cdot 22500}{2 \cdot 1}

(- 300)^{2} - 4 \cdot 1 \cdot 22500 = 0

x_{1, 2} = \frac{- ( - 300 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 300 )}{2 \cdot 1}

\frac{- ( - 300 )}{2 \cdot 1} = 150

x = 150

The solution to the quadratic equation is:

x = 150

x^{2} + 10 = 1

x^{2} - 3 x = 12

\frac{2}{3} x^{2} - 5 = 1

\frac{1}{2} u^{2} + u = 5

x + 9 = x^{2} + 20 x + 100

What are the solutions to the equation 0.1x^2-30x+2250=0 ?
The solutions to the equation 0.1x^2-30x+2250=0 are x=150
Find the zeros of 0.1x^2-30x+2250=0
The zeros of 0.1x^2-30x+2250=0 are x=150