What are the solutions to the equation 0.3x^2+1.2x+5=0 ?

The solutions to the equation 0.3x^2+1.2x+5=0 are x=-2+isqrt(38/3),x=-2-isqrt(38/3)

Find the zeros of 0.3x^2+1.2x+5=0

The zeros of 0.3x^2+1.2x+5=0 are x=-2+isqrt(38/3),x=-2-isqrt(38/3)

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0.3 x^{2} + 1.2 x + 5 = 0

x = - 2 + i \frac{38}{3}, x = - 2 - i \frac{38}{3}

Solution steps

0.3 x^{2} + 1.2 x + 5 = 0

Multiply both sides by

10

3 x^{2} + 12 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 50}{2 \cdot 3}

Simplify

1 2^{2} - 4 \cdot 3 \cdot 50 : 2114 i

x_{1, 2} = \frac{- 12 \pm 2 114 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 2 114 i}{2 \cdot 3}, x_{2} = \frac{- 12 - 2 114 i}{2 \cdot 3}

x = \frac{- 12 + 2 114 i}{2 \cdot 3} : - 2 + i \frac{38}{3}

x = \frac{- 12 - 2 114 i}{2 \cdot 3} : - 2 - i \frac{38}{3}

The solutions to the quadratic equation are:

x = - 2 + i \frac{38}{3}, x = - 2 - i \frac{38}{3}

x, y = x^{2} - 2 x

x^{2} - 6 x - 92 = - 7 x - 2

x^{2} - 3 x - 180 = 0

x^{2} + 15 x - 4 = 9 x + 3

2 (x^{2} - 1) = x

What are the solutions to the equation 0.3x^2+1.2x+5=0 ?
The solutions to the equation 0.3x^2+1.2x+5=0 are x=-2+isqrt(38/3),x=-2-isqrt(38/3)
Find the zeros of 0.3x^2+1.2x+5=0
The zeros of 0.3x^2+1.2x+5=0 are x=-2+isqrt(38/3),x=-2-isqrt(38/3)