What are the solutions to the equation (2x+10)^2=16 ?

The solutions to the equation (2x+10)^2=16 are x=-3,x=-7

Find the zeros of (2x+10)^2=16

The zeros of (2x+10)^2=16 are x=-3,x=-7

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(2 x + 10)^{2} = 16

x = - 3, x = - 7

Solution steps

(2 x + 10)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x + 10 = 16 : x = - 3

Solve

2 x + 10 = - 16 : x = - 7

The solutions to the quadratic equation are:

x = - 3, x = - 7

- 15 x^{2} + 47 = - 13

0 = 5 x^{2} - 5

\frac{15 c ^{2} - 8 c}{3} = 4

7 x^{2} - 2 x + 3 = 5 x^{2} - 10

7 x (x - 8) = 0

What are the solutions to the equation (2x+10)^2=16 ?
The solutions to the equation (2x+10)^2=16 are x=-3,x=-7
Find the zeros of (2x+10)^2=16
The zeros of (2x+10)^2=16 are x=-3,x=-7